mars.tensor.fmax¶

mars.tensor.
fmax
(x1, x2, out=None, where=None, **kwargs)[source]¶ Elementwise maximum of array elements.
Compare two tensors and returns a new tensor containing the elementwise maxima. If one of the elements being compared is a NaN, then the nonnan element is returned. If both elements are NaNs then the first is returned. The latter distinction is important for complex NaNs, which are defined as at least one of the real or imaginary parts being a NaN. The net effect is that NaNs are ignored when possible.
 x1, x2 : array_like
 The tensors holding the elements to be compared. They must have the same shape.
 out : Tensor, None, or tuple of Tensor and None, optional
 A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshlyallocated tensor is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
 where : array_like, optional
 Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
**kwargs
 y : Tensor or scalar
 The maximum of x1 and x2, elementwise. Returns scalar if both x1 and x2 are scalars.
 fmin :
 Elementwise minimum of two tensors, ignores NaNs.
 maximum :
 Elementwise maximum of two tensors, propagates NaNs.
 amax :
 The maximum value of an tensor along a given axis, propagates NaNs.
 nanmax :
 The maximum value of an tensor along a given axis, ignores NaNs.
minimum, amin, nanmin
The fmax is equivalent to
mt.where(x1 >= x2, x1, x2)
when neither x1 nor x2 are NaNs, but it is faster and does proper broadcasting.>>> import mars.tensor as mt
>>> mt.fmax([2, 3, 4], [1, 5, 2]).execute() array([ 2., 5., 4.])
>>> mt.fmax(mt.eye(2), [0.5, 2]).execute() array([[ 1. , 2. ], [ 0.5, 2. ]])
>>> mt.fmax([mt.nan, 0, mt.nan],[0, mt.nan, mt.nan]).execute() array([ 0., 0., NaN])